Atoms and Molecules
Acids, bases and the Henderson-Hasselbalch
Equation
An acid is a substance which produces hydrogen ions (H+) by
dissociation.
For example
HCl H+
+ Cl-
Bases are substances which can combine with H+
like ammonia (NH3)
For example H+
+ NH3
NH4+
They may produce hydroxide ions (OH- ) either by direct dissociation
or subsequent to reaction with water,
e.g.
KOH K+
+ OH-
and
NH3 + H2O
NH4OH
NH4+ + OH-
Hydrogen ions (H+) associate with water to form
H3O+ (and H11O5+ etc.)
Water
dissociates to a tiny extent: H2O
H+ + OH-
The equilibrium constant = Keq
= 1.8 x 10-16 = [H+]x[OH-]
= [H+]x[OH+] (see
footnote 1)
[H2O]
(1000/18)
Therefore
[H+]x[OH- ] = 1.8 x 10-16 x 55.5 = 10-14
In pure water [H+] must equal [OH-]
(the solution is neutral),
therefore [H+] = Ö10-14
= 10-7 M
The pH (hydrogen ion potential) of a solution is defined
as pH = -log10 (H+) , where (H+) is the
hydrogen ion concentration. The pH scale can range between about -1 and +15; a
neutral solution has pH 7.0.
For a weak acid, which dissociates as follows: HA
H+ + A-
![[Ka=(H+ x A- )/HA]](images/acids17.gif)
An interesting and extremely useful relationship between
pH and pKa can be obtained simply by taking logarithms (to the base
10; see footnote 2) of the above:
log10Ka = log10[H+]
+ log10[A- ] - log10[HA]
Therefore
-log10[H+] = -log10Ka + log10[A-]
- log10[HA]
giving the Henderson-Hasselbalch equation:
The most convenient form of this Henderson-Hasselbalch equation, is
![[Henderson-Hasselbalch equation; ph=pka+log10([proton acceptor]/[proton donor])]](images/acids19.gif)
By using pKa values, we are able to express the
strength of an acid (i.e. its tendency to dissociate) with reference to the pH
scale. If Ka, the dissociation constant, is large, then pKa
will have a low numerical value. A strong acid is one which is largely, perhaps
completely, dissociated, and which therefore has a high Ka value. A
weak acid is one that is only slightly dissociated in solution, and has a low Ka
value. There is no generally accepted dividing line between weak and strong
acids, but as a rough guide it is suggested that a strong acid would be at least
25% dissociated in a 0.1 M solution; this corresponding to Ka of
about 10-2. If Ka = 10-2, the corresponding pKa
value is (+) 2.0. Lower values of pKa (e.g. 0.7) correspond to
stronger acids (Ka = 0.2), while higher values (e.g. 4.7) correspond
to weaker acids (Ka = 2 x 10-5). pKa values are
used both for acids and for the conjugate acids of bases. Thus NH3
has pKa (for the dissociation NH4+
H+ + NH3) about 9.3. There is no real need for Kb
(and pKb) values, given by Kb = [BH+][HO-]/[B][H2O].
Should such values ever be required, for dilute aqueous solutions Kb
= 10-14/Ka and pKb = 14.0 - pKa
where Kb and pKb refer to the conjugate acid (BH+
H+
+ B).
Perhaps it is useful to look at this in another way: if we
consider the situation where the acid is one half dissociated, in other words
where [A-] is equal to [HA], then, substituting in the Henderson-Hasselbalch
Equation
pH = pKaa + log10(1)
Therefore
pH = pKa + 0
Therefore
pH = pKa
This means that an acid is half dissociated when the pH of
the solution is numerically equal to the pKa of the acid. Therefore
acids with the lowest pKa values are able to dissociate in solutions
of low pH, i.e. even where the hydrogen ion concentration is high. Acids with
higher pKa values dissociate only in solutions of high (more
alkaline) pH.
|
Acid
|
Ka
|
|
pKa
|
|
Trichloroacetic
|
2 x10-1
|
=10-0.7
|
0.7
|
|
Dichloroacetic
|
5 x10-2
|
=10-1.3
|
1.3
|
|
Monochloroacetic
|
1.6 x10-3
|
=10-2.8
|
2.8
|
|
Formic
|
2.1 x10-4
|
=10-3.7
|
3.7
|
|
Benzoic
|
7.8 x10-5
|
=10-4.1
|
4.1
|
|
Acetic
|
1.9 x10-5
|
=10-4.7
|
4.7
|
|
H2CO3
|
2.9 x10-7
|
=10-6.5
|
6.5
|
|
H2S
|
5.8 x10-8
|
=10-7.2
|
7.2
|
|
HCN
|
1.3 x10-9
|
=10-8.9
|
8.9
|
The table above gives some examples of Ka and
pKa values for a number of acids, which are listed in order of
decreasing strength.
Buffers
A buffer is a mixture of dissolved substances which tends
to keep the pH of a solution constant when modest additions of acid or base are
made to that solution. No buffer can keep the pH exactly constant in such
situations. The Henderson-Hasselbalch equation is very useful for calculations
involving buffers, and is fairly accurate under reasonable conditions.
Practical buffers consist of mixtures of weak acids and their salts. They will
buffer solutions over a range of pH about 1 unit either side of the pKa
value.
![[titration]](images/acids20.gif)
Polybasic acids or mixtures of acids will have several pKa
values, and (when mixed with their salts) can therefore buffer over several
ranges of pH. Provided the individual pKa values differ by less than
2 units, the mixture will show more or less continuous buffering over a wide
range of pH. For example, citric acid (pKa values 3.1, 4.8, and 6.4)
mixed with one of its salts such as trisodium citrate will buffer continuously
from pH 2 to 7.5, but not at higher pH values. A mixture of "Tris" (tris(hydroxymethyl)aminomethane,
pKa 8.1), trimethylamine (pKa 9.8), and piperidine (pKa
11.1) together with (say) their hydrochlorides, will buffer from pH about 7 to
12. These three bases with citric acid would buffer at all pH values between
about 2 and 12.
The Henderson-Hasselbalch equation is used for the
calculation of the pH or composition of a buffer solution. With mixtures
consisting of weak acids (only slightly dissociated) and their salts (nearly
totally ionised) the convenient approximations [HA] = total acid concentration,
and [A- ] = salt concentration, can often be made. This is adequate
for most buffer design purposes, the exact pH required being obtained by
adjusting the composition by adding a little strong acid or base. Hence an
acetic acid/acetate buffer solution containing 0.1 M acetic acid and 0.05 M
sodium acetate would have a pH of 4.4.
pH = pKa
+ log10[conjugate base] = 4.7 + log10(0.05)
= 4.7 + (-0.3) = 4.4
[conjugate
acid]
(0.1)
Buffers function as follows: when a strong acid is added,
the H+ from that acid combine with a portion of the anion to form
undissociated acid, thereby removing most of the added H+ from the
solution
H+ + A-
HA
When strong base is added part of the undissociated acid
reacts to form anions
Base + HA
A- + BaseH+
For further information, do look at the 'pH/Titrations'
PC program.
Notes
1. Square brackets means
“concentration of” whatever they contain; e.g. [H+] means the
concentration of hydrogen ions in moles per litre. (Back)
2. If this derivation
presents any difficulty then you are reminded of the following relationships:
- log (x x y) = log (x) + log (y)
- log (x/y) = log (x) - log (y)
- log (1/x) = -log (x)
- log (1) =
0
(Back)
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This page was last updated by Martin
Chaplin
on
10 February, 2005
|